Question 740620
There's two squares. Ones bigger than the other. The area of the bigger square is twice the area of the smaller. The total perimeter of the squares together is 16 inches. What's the side lengths of the larger square?
--------
Smaller Square:
Area = 4x^2 ; side = 2x ; Perimeter = 4*2x = 8x
----
Larger Square:
Area = 8x^2 ; side = 2^(3/2)x ; Perimeter = 4*2^(3/2)x = 2^(7/2)x
------
Equation:
Sum of Perimeters = 16
-----
8x + 2^(7/2)x = 16
(8+8sqrt(2))x = 16
19.313x = 16
x = 0.8284 inches
------
Smaller side length = 2x = 1.657
Larger side length = 2^(3/2)x = 2.3431
============
Cheers,
Stan H.
=======================