Question 740455


Using the slope-intercept form,

{{{y=mx+b}}} where {{{m=slope}}}, {{{b=y-intercept}}},

and substituting the values {{{m=6/7}}} and {{{b=-3}}}, we get


{{{y=(6/7)x-3}}}


 {{{ graph( 500, 500, -10, 10, -10, 10, (6/7)x-3) }}}