Question 740057
{{{x=7-2y}}}...eq.1
{{{2x+y=5}}}...eq.2
________________________

{{{x=7-2y}}}...eq.1.substitute {{{x}}} in eq.2


{{{2(7-2y)+y=5}}}...eq.2...solve for {{{y}}}

{{{14-4y+y=5}}}

{{{14-3y=5}}}

{{{14-5=3y}}}

{{{9=3y}}}

{{{9/3=y}}}


{{{highlight(3=y)}}}

now find {{{x}}}

{{{x=7-2y}}}...eq.1

{{{x=7-2*3}}}

{{{x=7-6}}}

{{{highlight(x=1)}}}


check solution on a graph:


{{{ drawing ( 600, 600, -10, 10, -10, 10,circle(1,3,0.2),grid(1),graph( 600, 600, -10, 10, -10, 10,7/2-x/2, -2x+5)) }}}