Question 739965
let the 4 numbers be 
a-3d,a-d,a+d,a+3d

a-3d+a-d+a+d+a+3d=4

4a=4
a=1

(a-d)(a+d)+(a-3d)(a+3d)=-3


a^2-d^2+a^2-9d^2=-3

2a^2-10d^2=-3

but a=1
2-10d^2=-3
10d^2=5

d^2=1/2

d= +/- 1/sqrt(2)

1-(3/sqrt(2)), 1-1/sqrt(2),1+1/sqrt(2), 1+(3/sqrt(2))

plug d= -1/sqrt(2) and get the other 4 numbers