<PRE><B>Question 739877</B>
Find 3 consecutive integers such that the product of the 2 larger integers is 50 more than 5 times the smallest integer.
*** 
let x=smallest consecutive integer
(x+1)=next consecutive integer
(x+2)=largest consecutive integer
..
product of the 2 larger integers=(x+1)(x+2)
5 times the smallest integer=5x
adding 50 to the 5 times the smallest integer to set up the equation. 
(x+1)(x+2)=50+5x
x^2+3x+2=50+5x
x^2-2x-48=0
(x-8)(x+6)=0
x=8
or
x=-6
..
For positive integers:
smallest consecutive integer=8
next consecutive integer=9
largest consecutive integer=10
..
For negative integers:
smallest consecutive integer=-6
next consecutive integer=-5
largest consecutive integer=-4
</PRE>