Question 739876
133(b)+6(c)=1000
2.07(b)+0.2(c)=8


133b+6c=1000
2.07b+0.2c=8




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Solve equation 1 for 'c'


133b+6c=1000


6c=1000-133b


c=(1000-133b)/6


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Plug this into the second equation


2.07b+0.2c=8


2.07b+0.2( (1000-133b)/6 )=8


2.07b+(0.2*1000-0.2*133b)/6=8


2.07b+(200-26.6b)/6=8


6*2.07b+6*(200-26.6b)/6=6*8 ... Multiply EVERY term by the LCD 6 to clear out fractions


12.42b + 200 - 26.6b = 48


-14.18b + 200 = 48


-14.18b = 48 - 200


-14.18b = -152


b = -152/(-14.18)


b = 10.71932299 (this is approximate)


c = (1000-133b)/6


c = (1000-133*10.71932299)/6


c = (1000-1425.66995767)/6


c = -425.66995767/6


c = -70.944992945 (this is approximate too)


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So the approximate solutions are


b = 10.71932299 


c = -70.944992945