Question 739602
Same method as the other equation to find foci and vertex
parabola
focus | (0, -3/2)
vertex | (0, 0)
semi-axis length | 3/2 = 1.5
focal parameter | 3
eccentricity | 1
directrix | y = 3/2

This is from Wikipedia - "In Cartesian coordinates, a parabola with an axis parallel to the y axis with vertex (h, k), focus (h, k + p), and directrix y = k - p, with p being the distance from the vertex to the focus, has the equation (x-h)^2=4p(y-k)"