Question 64499
Solve for x using the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{7x^2 + 10x = -2}}} Add 2 to both sides.
{{{7x^1 + 10x + 2 = 0}}} Here, a = 7, b = 10, and c = 2
{{{x = (-10+-sqrt(10^2-4(7)(2)))/2(7)}}} Simplify this.
{{{x = (-10+-sqrt(156))/14}}}
{{{x = (-10/14)+(2sqrt(39))/14}}} and {{{x = (-10/14)-(2sqrt(39))/14}}} Simplifying a bit more.
{{{x = (-5/7)+(sqrt(39))/7}}} = {{{(-5+sqrt(39))/7}}} and...
{{{x = (-5/7)-(sqrt(39))/7}}} = {{{(-5-sqrt(39))/7}}}