Question 739546
let U-Haul charges a daily fee of x & a mileage charge of y to rent a truck. 
Jennifer rented a truck with U-Haul and was charged $132 for 3 days rental and 150 miles driven. 
so 3x+150y=132...........1
 Nigel was charged $142 for 2 days rental and 400 miles driven.
so 2x+400y=142...........2
now multiplying eqn 1 by 2 & eqn 2 by 3 & subtracting 
6x+300y=264...........3
6x+1200y=426.............4
- -     -
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-900y=-162
or y=162/900=0.18
from eqn 1 
3x=132-400 X 0.18=60
or x=60/3=20
now we can frame an set up a system of linear equation to determine the total fee for n days & m miles as
total fee=0.18 X n +20 X m