Question 738549

you are given a line {{{ y=-2x+1}}}, and it is already in {{{slope-intercept}}} form {{{y=mx+b}}} where {{{m=slope}}} and {{{b=y-intercept}}}

so, the slope of given line {{{ y=-2x+1}}} is {{{m=-2}}}

by definition, a line parallel to given line has same slope; so, {{{m[p]=-2}}}