Question 738545
The question only needs find x when y=0.  The steps are uncomplicated because the equation is already in standard form.


{{{4(x+4)^2-12=0}}}
{{{(x+4)^2=12/4}}}
{{{(x+4)^2=3}}}
{{{x+4= +- sqrt(3)}}} [not sure if this line is rendering properly.]
{{{highlight(x=-4 +- sqrt(3))}}}