Question 64444
{{{ f(x) = 5x^2 / (x-2)}}}
f(-1) = ?
Just substitute -1 for x everywhere you see x in the function
{{{f(-1) = 5*(-1)^2 / (-1 -2)}}}
{{{f(-1) = 5 / (-3)}}}
{{{f(-1) = -(3/5)}}}
f(3) = ?
{{{f(3) = 5*3^2 / (3 - 2)}}}
{{{f(3) = 45 / 1}}}
{{{f(3) = 45}}}
If you do the long division, you get
{{{5x^2 / (x-2) = 5x + 10 + 20 / (x-2)}}}
As x grows positively, the 1st term gets more positive and the last term approaches zero.
As x grows negatively, the 1st term gets more negative, and the last term
still approaches zero.
When x = +2, the last term becomes +infinity.
So, the domain of this is  +2 < x < +2