Question 738448
As you should have learned intercepts occur when the line intersects the x or y axis. Think about when a line will intercept the x axis..... When {{{y = 0}}} and the same for the y intercept.... When {{{x = 0}}}. So what you need to do to find the intercepts in our example is set the x or y value to 0 and solve for the other variable. The equation you gave is {{{y = x^2 + 8}}}. So first we will set {{{x = 0}}}, so the new equation is {{{y = 0^2 + 8}}}. So as we know 0 to any power will always be 0 so if we simplify we get {{{y = 8}}}. This means when you x value equals 0 you y value equals 8, this is you y intercept. Then we do the same for x. First we set {{{y = 0}}} and then adjust your equation to be {{{0 = x^2 + 8}}} then we simplify... but we run into a problem when we reach {{{ -8 = x^2}}}, we can not square root negative numbers or we get a imaginary answer. This means that we have no x intercept. So our only intercept is (8, 0)