Question 738376


{{{10c^2+25c-6c-15}}} Start with the given expression



{{{(10c^2+25c)+(-6c-15)}}} Group the terms in two pairs



{{{5c(2c+5)-3(2c+5)}}} Factor out the GCF {{{5c}}} out of the first group. Factor out the GCF {{{-3}}} out of the second group



{{{(5c-3)(2c+5)}}} Since we have the common term {{{2c+5}}}, we can combine like terms



So {{{10c^2+25c-6c-15}}} factors to {{{(5c-3)(2c+5)}}}



In other words, {{{10c^2+25c-6c-15=(5c-3)(2c+5)}}}