Question 737799
How do you find an equation of the parabola with vertex (-3,-4) and focus (-3,-3)?
This is a parabola that opens upward:
Its basic equation: {{{(x-h)^2=4p(y-k)}}}, (h,k)=(x,y) coordinates of the vertex
For given parabola:
vertex: (-3,-4)
axis of symmetry: x=-3
p=1 (distance from vertex to focus on the axis of symmetry)
4p=4
Equation:  {{{(x+3)^2=4(y+4)}}}