Question 738044
"True or false? 2r3 + 3r2 − 18r − 27 = 0 has solutions 3, -3, and 3/2."
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{{{f(r) = 2r^3 + 3r^2 - 18r - 27}}}
f(3) = 54 + 27 - 54 - 27 = 0
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f(-3) = -54 + 27 + 54 - 27 = 0
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f(3/2) = 27/4 + 27/4 - 27 - 27 = -81/2
Not a zero --> false
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