Question 64365
3ac/x^2 + 2 / z^2 
DIVIDED BY
1 - 4/ x^2z^2
:
Use the common denominator to put them into single fractions
{{{(3ac/x^2) + (2 / z^2)}}} = {{{(3acz^2 + 2x^2)/(x^2z^2)}}}

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{{{1 - (4/x^2z^2) }}} = {{{(x^2z^2 - 4)/x^2z^2) }}}
:
When you divide fractions, invert the dividing fraction and mult, cancel x^2z^2's
:
{{{(3acz^2 + 2x^2)/(x^2z^2)}}} * {{{(x^2z^2)/(x^2z^2 - 4)}}} =   {{{(3acz^2 + 2x^2)/(x^2z^2 - 4)}}}