Question 738012
for angle {{{32}}}°{{{20}}}' the complement is  

{{{90}}}°-({{{32}}}°{{{20}}}')......take on degree from {{{90}}}° and convert in minutes


({{{89}}}°{{{60}}}')-({{{32}}}°{{{20}}}')...now subtract degrees from degrees and minutes from minutes


({{{89}}}°-{{{32}}}°)({{{60}}}'-{{{20}}}')

{{{57}}}°{{{40}}}'

supplement

{{{180}}}°-({{{32}}}°{{{20}}}')......take on degree from {{{180}}}° and convert in minutes


({{{179}}}°{{{60}}}')-({{{32}}}°{{{20}}}')...now subtract degrees from degrees and minutes from minutes


({{{179}}}°-{{{32}}}°)({{{60}}}'-{{{20}}}')

{{{147}}}°{{{40}}}'