Question 737927
graph of the function -2(x - 1)^2 = y + 5
This is an equation of a parabola that opens downward:
Its standard (vertex) form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex. A is a coefficient that affects the slope or steepness of the curve.
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For given equation: -2(x - 1)^2 = y + 5
rearrange terms to standard form:
{{{y= -2(x-1)^2+5}}}
A=-2
vertex: (1,5)
axis of symmetry: x=1
y-intercept
set x=0
y=-2+5=3
see graph below:
{{{ graph( 300, 300, -10,10, -10, 10, -2(x-1)^2+5) }}}