Question 737825
All quadratic equations can be solved by the quadratic equation which is {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

Lets start by defining a, b, and c

a=1
b=-4
c=-32

Now we substitute the variables for the numbers and solve the equation
{{{x=-(-4)+sqrt((-4)^2-4*1*-32))/(2*1) }}} and {{{x=-(-4)-sqrt((-4)^2-4*1*-32))/(2*1) }}}

Simply both equations
{{{x=(4+12)/2}}} and {{{x=(4-12)/2}}}
{{{x=16/2}}} and {{{x=-8/2}}}
x=8 and -4