Question 737758
{{{f(t)=Ae^(rt)}}} where A=initial amount =100, t=number of hours and r=rate

so {{{f(6.5)=100e^(6.5r)=350}}}

this gives {{{e^(6.5r)=350/100=3.5}}}

so {{{ln(e^(6.5r))=ln(3.5)}}}

so {{{6.5r = ln(3.5)}}}

and {{{r=ln(3.5)/6.5=.193}}}

Now to find out when t=14

{{{f(14)=100e^(14*(.193))=100e^(2.702)=1490.952}}}