Question 737497
(a) 
The rate of melting is ( change in acres ) / ( years passed )
Rate = {{{  ( 1 - 10 ) / ( 2003 - 1918 )  }}}
Rate = {{{ (-9) / 5 = -9/5 }}}
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(b)
{{{ A = m*t + b }}}, where
{{{ A }}} = acres covered
{{{ t }}} = time in years
{{{ m }}} = slope from part (a)
{{{ b }}} = {{{ A }}} -intercept, where {{{ t = 0 }}}
( I am saying that 1918 is {{{ t=0 }}} )
In 1918,  {{{ A = 10 }}}
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{{{ A = (-9/5)*t + 10 }}}
check:
when {{{ t = 5 }}}
{{{ A = -9 + 10 }}}
{{{ A = 1 }}} acre
OK