Question 737137
we are given

3i + 2j = 4

and 2j - 2i = 6

therefore 2j = 2i + 6  and

j = i + 3

substitute in the first equation

3i + 2 * (i+3) = 4

3i + 2i + 6 = 4

5i = -2

i = -2/5 and  -6/5 + 2j = 4, -6 + 10j = 20, j = 26/10 = 13/5

i = -2/5 and j=13/5