<PRE><B>Question 737197</B>
Simplify/solve each one using algebra.&lt;P&gt;
{{{x^3 &gt;= x^2}}}  Divide both sides by {{{x^2}}}&lt;P&gt;
{{{x&gt;= 1}}}  That&#39;s only true for real numbers 1 or greater.&lt;P&gt;
{{{3x^2 &gt;= 2x^3}}} Divide both sides by {{{x^2}}} and divide both sides by 2.&lt;P&gt;
{{{3/2 &gt;= x}}} Only true for real numbers less than or equal to 3/2.&lt;P&gt;
{{{(2x)^2 &gt;= 3x^2}}}&lt;P&gt;
{{{4x^2 &gt;= 3x^2}}} Divide both sides by {{{x^2}}}&lt;P&gt;
{{{4 &gt;= 3}}} That&#39;s always true.  &lt;P&gt;
{{{3(x-2)^2 &gt;= 3x^2 - 2}}}&lt;P&gt;
{{{3x^2 - 12x +12 &gt;= 3x^2 - 2}}}&lt;P&gt;
{{{-12x &gt;= -14}}}&lt;P&gt;
{{{x&gt;= 7/6}}}  Not true for all real numbers.
&lt;P&gt;Hope the solution helped.  Sometimes you need more than a solution.  Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)
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