Question 737103


Since the square is inscribed in a circle, the {{{vertices}}} of the square touches the circle. Hence the {{{diameter}}} of the circle is the {{{diagonal}}} of the square. 

Now, the length of the diagonal is obtained by using Pythagoras theorem, and  the area and the {{{diameter}}} is

{{{d^2=5^2+5^2}}}

{{{d^2=25+25}}}

{{{d^2=50}}}

{{{d=sqrt(50)}}}

{{{d=7.07}}}

then radius is {{{r=d/2=7.07/2=3.535}}}

so, the circumference of the circle is:

{{{circumference=2r*pi}}}

{{{circumference=2*3.535*3.14}}}

{{{circumference=22.1998}}}