Question 736986
general formula is:

{{{a[n]=8n^3+4n^2-4n+1}}}

check if it works with first two terms:

{{{a[1]=8*1^3+4*1^2-4*1+1}}}
{{{a[1]=8+4-4+1}}}
{{{a[1]=13-4}}}
{{{a[1]=9}}}

{{{a[2]=8*2^3+4*2^2-4*2+1}}}
{{{a[1]=8*8+4*4-4*2+1}}}
{{{a[2]=64+16-8+1}}}
{{{a[2]=81-8}}}
{{{a[2]=73}}}

so, next term in {{{a[1]=9}}},{{{a[2]=73}}}, {{{a[3]=241}}},{{{a[4]=561}}},{{{a[5]=1081}}}, {{{a[6]=1849}}}, that we are looking for is {{{a[7]}}}


{{{a[7]=8*7^3+4*7^2-4*7+1}}}

{{{a[7]=2744+196-28+1}}}

{{{a[7]=2913}}}