Question 737043
We are using these 3 rules (in the same order)


Rule 1) 1/x = x^(-1)


Rule 2) log(x^y) = y*log(x)


Rule 3) log base b (b) = 1 ... ex: {{{log(2,(2))=1}}}, {{{log(17,(17))=1}}}


-------------------------------------------------------


Log base 6 (1/6) = Log base 6 (6^(-1)) ... use rule 1 above


Log base 6 (1/6) = -1*Log base 6 (6) ... use rule 2 above


Log base 6 (1/6) = -1*1 ... use rule 3 above


Log base 6 (1/6) = <font color="red">-1</font>