Question 737008
log(base7)x+log(base7)(x-1)=log(base7)12
{{{log(7,(x))+log(7,(x-1))=log(7,(12))}}}
{{{x(x-1)=12}}}
{{{x^2-x-12=0}}}
(x-4)(x+3)=0
x=-3 (reject, x>0)
x=4