Question 736980
log a - log b = log (a/b).  <P>
log ((7x+33)/6) = log(4x-3)<P>
raise 10 to the power of both sides of the equation.  That will remove the log (base 10).  10 ^ (log((7x+33)/6) = (7x+33)/6.  10^(log(4x-3)) =  4x-3.   <P>
(7x+33)/6 = 4x-3<P>
7x+33 = 24x-18<P>
51 = 17x<P>
3=x
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