Question 736727
Given that log_7(y) = -15.15, log_7(r) = -17.11, and log_7(x) = 7.99, find the following: 
log_7((y^6r^4)/x^7)
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{{{log(7,(y^6r^4))-7log(7,(x)))}}}
{{{6log(7,(y))+4log(7,(r))-7log(7,(x)))}}}
{{{6*-15.15+4*-17.11-7*7.99=-215.27}}}