Question 736736
The other tutor did a lot of work and left off here:
{{{(2(16x^2-64x+28))/((48x^2-136x+56))}}}
= {{{(4x^2-16x+7)/(6x^2-17x+7)}}}
= {{{(2x-1)(2x-7)/((3x-7)(2x-1))}}}
= {{{(2x-7)/(3x-7)}}}