Question 736770
f(x) = 3x2 + 6x + 1


On X axis y=0

3x^2+6x+1=0

Find the roots of the equation by quadratic formula							
							
a=	3	b=	6	c=	1		
							
b^2-4ac=	36	-	12				
b^2-4ac=	24			{{{sqrt(	24	)}}}=	4.9
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	-6	+	4.9	)/	6		
x1=	-0.18						
x2=(	-6	-4.9	) /	6			
x2=	-1.82						


Intersection at -0.18 and -1.82