Question 736666
we know length (l) * width (w) = Area (A) for a rectangle  and

2*l + 2*w = Perimeter (P)

we are given l * w = 188 (A)

let's list the factors as pairs (l, w) when multiplied together give 188

(188, 1), (94, 2), (47, 4)

it remains to calculate the pair with the smallest perimeter

(188, 1) = 2*188 + 2*1 = 378 (P)
(94, 2) = 2*94 + 2*2 = 192 (P)
(47, 4) = 2*47 + 2*4 = 102 (P)

therefore the rectangle with length 47 and width 4 has the shortest Perimeter