Question 736550
<pre>
log<sub>2</sub>(5x + 2) = 4

Use the definition of a logarithm which states that the
logarithm equation {{{log(B,A)=C}}} is equivalent to the
exponential equation {{{A=B^C}}}.

Therefore your logarithm equation is equivalent to this
exponential equation:

5x + 2 = 2<sup>4</sup>
5x + 2 = 16
    5x = 14
     x = {{{14/5}}} or 2.8

Edwin</pre>