<PRE><B>Question 736552</B>
&lt;pre&gt;
log&lt;sub&gt;3&lt;/sub&gt;(3x - 3) = 2

Use the definition of a logarithm which states that the
logarithm equation {{{log(B,A)=C}}} is equivalent to the
exponential equation {{{A=B^C}}}.

Therefore your logarithm equation is equivalent to this
exponential equation:

3x - 3 = 3&lt;sup&gt;2&lt;/sup&gt;
3x - 3 = 9
    3x = 12
     x = 4

Edwin&lt;/pre&gt;



 

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