Question 736462
This looks like {{{ 0 }}} to me
{{{ 2*pi }}} is a complete circle, and
so are {{{ 4*pi }}} and {{{ 6*pi }}}
coming back to {{{ 0*pi }}}
{{{ 6*pi + pi }}} brings you to {{{ pi }}}
and the {{{ sin( pi ) = 0 }}}, so the
expression is {{{ 0 }}}