Question 736421
2      	x	+	1	y  	=	2				
Find the slope of this line										                                                                                                            
										
1	y  	=	-2      	x	+	2    				
Divide by	1									
	y  	=	-2      	x	+	2    				
Compare this equation with y=mx+b,					m= slope & b= y intercept					
slope m =	-2    									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										 1/2
Because m1*m2 =-1										
The slope of the required line will be			 1/2							
										
m=	 1/2	,point	(	4	,	7	)			
Find b by plugging the values of m & the point in										
y=mx+b										
7	=	2      	+	b						
b=	5    									
m=	 1/2									
The required equation is y  	=	  1/ 2	x	+	5      



where do they intersect

2.00	x	+	1.00	y	=	2.00	.............1	
Total value								
-0.50	x	+	1.00	y	=	5.00	.............2	
Eliminate	y							
multiply (1)by		-1.00						
Multiply (2) by		1.00						
-2.00	x		-1.00	y	=	-2.00		
-0.50	x	+	1.00	y	=	5.00		
Add the two equations								
-2.50	x				=	3.00		
/	-2.50							
x	=	-1.20						
plug value of			x	in (1)				
2.00	x	+	1.00	y	=	2.00		
-2.40		+		y	=	2.00		
				y	=	2.00	+	2.40
				y	=	4.40		
				y	=	4.40		
			
(-1.20,4.40) (6,7)

Find the distance between the points. that's the length of the pipe line
Distance between two points													
x1	y1	x2	y2										
													
-1.2	4.4	6	7										
d=	{{{sqrt((y2-y1)^2+(x2-x1)^2)}}}												
d=	{{{sqrt((		7	-	4.4	)^2	+	(	6	-	-1.2	)^2	)}}}
d=	{{{sqrt((		2.6	)^2	+	(	7.2	)^2	)}}}				
d=	{{{sqrt((		58.6	)  	)}}}								
d=	7.66												
m.ananth@hotmail.ca													

m.ananth@hotmail.ca