Question 736425
First car	40	mph				
Car II	65	mph				
First car		09:00				
Car II		11:00				
Difference in time=		02:00	=>	2.00	hours	
First car	will have covered	80.00	miles		Car II	starts
catch up distance=		80.00	miles			
catch up speed =		65	-40			
catch up speed =		25	mph			
Catchup time = catchup distance/catch up speed						
catch up time=		3.2				
catch up time=		3.20	hours			
They will meet at		12:20	pm		
Car II	speed	=	65	hours		
Time to catch up		=	3.2			
D=Speed * time						
D=	65	*	3.2			
D=	208	miles				
Car II	will catch up	when it has traveled		208	miles