Question 736411
Assuming the problem is
{{{4^((5x-1))}}} = {{{2^((4-x))}}}
4 can be written as 2^2, therefore we have
{{{2^(2(5x-1))}}} = {{{2^((4-x))}}}
therefore
2(5x-1) = 4 - x
10x - 2 = 4 - x
10 + x = 4 + 2
11x = 6
x = {{{6/11}}}
:
:
Check this on a calc; 6/11 ~ .545
:
4^(5(.545)-1) ~ 10.93
2^(4-.545) ~ 10.97