Question 736398
Find the equation of a circle with (2,5) and (3,4) as end points of the diameter.
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Standard form of equation for a circle: {{{(x-h)^2+(y-k)^2=r^2}}}, (h,k)=(x,y) coordinates of center, r= radius
Use midpoint formula to find coordinates of center:
midpoint=(x1+x2)/2, (y1+y2)/2=(3+2)/2,(4+5)/2=(5/2,9/2)=(2.5,4.5)
center:(2.5,4.5)
use distance formula to find diameter: 
d=√[(x1-x2)^2+(y1-y2)^2]=√[(3-2)^2+(4-5)^2]=√(1+1)=√2
radius=d/2=√2/2
r^2=2/4=1/2
Equation of given circle:  {{{(x-2.5)^2+(y-4.5)^2=.5}}}