Question 736374
{{{x^2+4/x-1}}}={{{5/x-1}}}


{{{x^2+4/x-5/x-1}}}={{{-1}}}



{{{x^2+4/x-5/x}}}={{{-1+1}}}

{{{x^2-(1/x)}}}=0


{{{(x^3-1)/x =0}}}


{{{x^3=1}}}

since the index is odd

x=1