<PRE><B>Question 736309</B>
here you have to use the law of sines

let tree make an angle of 83 deg.with the ground. (YZ)angle ZYX = 83deg

he walks 100 feet away from tree to point X (YX)angle YXZ= 33 deg

so remaining angle YZX = 64 deg

triangle YXZ is formed

sin A /a = sin B /b = sin C /c

Sin YZX/100 = sin YXZ/ YZ

sin 64/100 = sin 33/YZ

100 * sin 33/sin 64 = YZ

100*0.54/0.898= YZ
YZ= 60.13 feet the height of the tree

You can solve the problem in a similar way if the tilt is to the other side.






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