Question 736265
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The other guy gave you the sum of the first 328 natural numbers.  You wanted the first 328 EVEN natural numbers.  The first of these is 2, and the last is 656 and we know that there are 328 numbers.


The sum of a series of numbers is given by *[tex \LARGE \frac{(a\ +\ l)n}{2}]


Where *[tex \LARGE a] is the first number (2 in this case), *[tex \LARGE l] is the last number (656 in this case), *[tex \LARGE n] is the number of numbers (328 in this case).  You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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