Question 736229
{{{l(t)=l[0]*e^(alpha*T)}}} and with {{{alpha=0.001}}} {{{l(t)=l[0]*e^(0.001T)}}}
 
When {{{T=10}}} {{{l(10)=l[0]*e^(0.001*10)=l[0]*e^0.01}}}
 
When {{{T=80}}} {{{l(80)=l[0]*e^(0.001*80)=l[0]*e^0.08}}}
 
{{{l(80)/l(10)=l[0]*e^0.08/(l[0]*e^0.01)=e^0.08/e^0.01=e^(0.08-0.01)=e^0.07}}}
 
The relative increase, as a fraction of the size at {{{t=10}}} is
{{{(l(80)-l(10))/l(10)=l(80)/l(10)-1=e^0.07-1}}}= approx. {{{1.0725-1=0.0725}}}
That is {{{0.0725/1=7.25/100=7.25}}}%