Question 736040


{{{2x(x-1)^3}}}....do first {{{(x-1)^3=(x-1)(x-1)^2=(x-1)(x^2-2x+1)=x^3-3x^2+3x-1}}}

{{{2x(x^3-3x^2+3x-1)}}}..now multiply by {{{2x}}}

{{{2x*x^3-2x*3x^2+2x*3x-2x*1)}}}

{{{2x^4-6x^3+6x^2-2x}}}