Question 735732
{{{5-2y>=0}}} or {{{5-2y<0}}}.  Solve {{{abs(5-2y)<11}}} for both cases.


{{{5-2y>=0}}} means {{{abs(5-2y)=5-2y}}}.
{{{5-2y<0}}} means {{{abs(5-2y)=-(5-2y)}}}.