Question 735753
...meaning you want to put the missing square term onto x(x+3/2), which as is, represents a rectangle which you can rearrange into a square missing a square corner.


{{{2x^2+3x-5}}}
{{{2(x^2+(3/2)x)-5}}}    ------- the term you want to use is {{{(3/(2*2))^2=9/16}}}
{{{highlight(2(x^2+(3/2)x+9/16)-2*(9/16)-5)}}} ------ADDING and SUBTRACTING the square term
{{{2(x+3/4)^2-9/8-5}}}
{{{2(x+3/4)^2-9/8-40/8}}}
={{{highlight(2(x+3/4)^2-49/8)}}}