Question 735714
How do you solve
7=5+sec(4x+7pi/4)
5+csc(2x+pi/3)=(15+2(sqrt(3)/3)
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7=5+sec(4x+7pi/4)
7-5=sec(4x+7pi/4)
2=1/cos(4x+7pi/4)
cos(4x+7pi/4)=1/2
{{{(4x+7pi/4)=inverse cos (1/2)=(pi/3)}}}
{{{4x=pi/3-7pi/4}}}
LCD:12
{{{48x=4pi-21pi}}}
{{{x=(-17pi/48)=-1.1126 (radians)}}}
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5+csc(2x+pi/3)=(15+2(sqrt(3)/3)
csc(2x+pi/3)=15+2(sqrt(3)/3)-5
csc(2x+pi/3)=10+2(sqrt(3)/3)≈11.1547
sin(2x+pi/3)=1/11.1547≈0.0896
2x+pi/3=inverse sin(0.0896)≈0.0897
2x=0.0897-pi/3≈-0.9575
x≈-0.4787 radians