Question 735645
(A)X^2-6X-3Y+3=0
(3,-2)=======(3,-5/4)===========Y=-11
VERTEX=======FOCI==============DIRECTRIX
(B)3X^2-12X+2Y-10=0
(2,11)=======(2,65/6)==========Y=67/6
VERTEX======FOCI==============DIRECTRIX
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