Question 735573
{{{f(x) = 4x-8}}}
What is the value of {{{f^(-1)(-2)}}}? 

first find inverse {{{f^(-1)(x)}}}


{{{f(x) = 4x-8}}} or {{{y = 4x-8}}}

{{{y = 4x-8}}}..switch {{{x}}} and {{{y}}}

{{{x = 4y-8}}}....solve for {{{y}}}

{{{x+8 = 4y}}}

{{{x/4+8/4 = y}}}

{{{x/4+2 = y}}}

so inverse of {{{f(x)=4x-8}}} is {{{f^(-1)(x)}=x/4+2 }}}

now find {{{f^(-1)(-2)}}} 

{{{f^(-1)(-2)=x/4+2 }}}...plug in {{{-2}}} for {{{x}}}

{{{f^(-1)(-2)=-2/4+2 }}}

{{{f^(1)(2)=-1/2+2 }}}

{{{f^(1)(2)=-1/2+4/2 }}}

{{{f^(1)(2)=3/2 }}}